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Elecric field intensity is 400 V m−1 at a distance of 2 m from a point charge. It will be 100 V m−1 at a distance?
- A 4 m
- B 4 cm
- C 1.5 m
- D 50 cm
That's Correct!
It's Wrong!
The electric field intensity decreases with distance from a point charge. Since the electric field intensity is 400 V m−1 at a distance of 2 m, it will be 100 V m−1 at a distance that is 4 times greater, which is 4 m.
